In the first part of this unit we consider sequences where the difference between successive terms is the same every time. We also use formulae to create the terms of a sequence.
Write down the next 3 terms of each of the following sequences:
7, 11, 15, 19, 23, ...
| 7 | 11 | 15 | 19 | 23 | ... |
| 4 | 4 | 4 | 4 |
7, 11, 15, 19, 23, 27, 31, 35
1, 9, 17, 25, 33, ...
| 1 | 9 | 17 | 25 | 33 | ... |
| 8 | 8 | 8 | 8 |
1, 9, 17, 25, 33, 41, 49, 57
A sequence is defined by the formula u_n = 3n + 1.
Calculate the first 5 terms of this sequence.
The first term, often called u_1, is formed by substituting
For the second term, substitute n = 2 to give:
u_2 = 3 × 2 + 1 = 7For the third term, substitute n = 3 to give:
u_3 = 3 × 3 + 1 = 10For the fourth term, substitute n = 4 to give:
u_4 = 3 × 4 + 1 = 13For the fifth term, substitute n = 5 to give:
u_5 = 3 × 5 + 1 = 16So the first 5 terms of the sequence are
4, 7, 10, 13, 16.
The terms of a sequence are given by the formula u_n = 8n – 3.
Calculate:
the first 3 terms of the sequence,
n = 1 gives u_1 = 8 × 1 – 3 = 5
n = 2 gives u_2 = 8 × 2 – 3 = 13
n = 3 gives u_3 = 8 × 3 – 3 = 21
So the first 3 terms are
5, 13, 21.
the 100th term of the sequence,
n = 100 gives u_100 = 8 × 100 – 3 = 797
So the 100th term of the sequence is 797.
the 200th term of the sequence.
n = 200 gives u_200 = 8 × 200 – 3 = 1597
So the 200th term of the sequence is 1597.