Unit 3 Section 2 : Laws of Indices
There are three rules that should be used when working with indices:
When
m and
n are positive integers,
| 1. | am × an = am + n |
| 2. | am ÷ an = am – n or |
| = am – n (m ≥ n) |
| 3. | (am)n = am × n |
These three results are logical consequences of the definition of an , but really need a formal proof. You can 'verify' them with particular examples as below, but this is not a proof:
| 27 × 23 | = | (2 × 2 × 2 × 2 × 2 × 2 × 2) × (2 × 2 × 2) | |
| = | 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 | |
| = | 210 | (here m = 7, n = 3 and m + n = 10) |
or,
| 27 ÷ 23 | = | | 2 × 2 × 2 × 2 × 2 × 2 × 2 | | 2 × 2 × 2 |
| |
| = | 2 × 2 × 2 × 2 | |
| = | 24 | (again m = 7, n = 3 and m – n = 4) |
Also,
| (27)3 | = | 27 × 27 × 27 |
| = | 221 | (using rule 1) (again m = 7, n = 3 and m × n = 21) |
The proof of the first rule is given below:
Proof
| am × an |
= |
a × a × ... × a
m of these |
× |
a × a × ... × a
n of these |
|
= |
a × a × ... × a × a × a × ... × a
(m+n) of these |
|
= |
am+n |
The second and third rules can be shown to be true for all positive integers
m and
n in a similar way.
We can see an important result using rule 2:
| | = xn – n = x0 |
| but | | = 1, | so |
x0 = 1
This is true for any non-zero value of x, so, for example, 30 = 1, 270 = 1 and 10010 = 1.