Powers
Fractional Indices

It may be useful to first revise our knowledge of how integer indices work.

Worked Examples

1

Complete these general statements:

For any non-zero number x, and any integers m and n:

(a)
x^m x^n = Show me x{m+n}
(b)
\frac{x^m}{x^n} = Show me x^{m-n}
(c)
(x^m)^n = Show me x^{mn}
(d)
x^0 = Show me 1
(e)
x^{-n} = Show me \frac{1}{x^n}

Expressions like 32, 410 and 10−6, all of which involve powers (or indices), will be familiar. But can any meaning be attached to an expression like 20.6 and if it can, does it have any relevance?

2

Bacteria perform the roles of friend and foe at the same time. They are micro-organisms that perform a crucial function in nature by causing plant and animal debris to decay in the soil, but at the same time they can cause disease. Under favourable conditions they reproduce freely. Lone bacterium will first split into two bacteria, then these will themselves split into two and so on.

This growth can be observed by placing a lone bacterium onto a petri dish and positioning the dish in a warm environment. The splitting process under these sorts of conditions will take place twice per hour; hence after one hour there will be 4 bacteria, after two hours 16 bacteria and so on.

(a)

Complete the table shown. Write a formula for the number of bacteria after t hours.

Time (hours)01234...t
Number of bacteria141664256...4t
Show me
(b)

Interpret this formula when t = , 1, 2, 3.

Show me

When t = Number of bacteria = 4 = 2

When t = 1 Number of bacteria = 4 = 8

When t = 2 Number of bacteria = 4 = 32

When t = 3 Number of bacteria = 4 = 128

3
(a)

Given that 20 = 1, 21 = 2, 22 = 4 and 23 = 8:

Draw an accurate graph of y = 2x by joining together these points with a curve drawn as smoothly as possible.

Show me

See the graph shown opposite.

(b)

The value of 21 must be double that of 2.

Why?

Make a similar statement about 22. Are these statements supported by your graph?

Show me

The value of 21 is double that of 2.

We have seen the value double each time the power increases by 1. The difference between 1 and 2 is indeed 1.

The value of 22 must be double that of 21.

These statements are supported by the graph shown.

(c)

What is your interpretation of 2?

Show me

2 is half of 21 (as the power has decreased by 1).

Some further logarithmic deductions are highlighted in the next worked example.
4
(a)

Let p stand for the value of 2 . What can you say about p2? What rule of indices did you use?

Show me

p^2 = 2 (2^{\frac{1}{2}})^2 = 2^1 (x^m)^n = x^{mn}

(b)

What is the meaning of x?

Show me

x^{\frac{1}{2}} = \sqrt{x}

(c)

Suppose q stands for the value of 2. What is q3?

Show me

q^3 = 2 (2^{\frac{1}{3}})^3 = 2^1 (x^m)^n = x^{mn}

(d)

What does x mean?

Show me

x^{\frac{1}{3}} = \sqrt[3]{x}

In general,

x^{\frac{1}{2}} is another way of writing \sqrt{x}

x^{\frac{1}{3}} is another way of writing \sqrt[3]{x}

x^{\frac{1}{n}} is another way of writing \sqrt[n]{x}

This alternative notation is often used on calculators. Your calculator may have a function x^{\frac{1}{y}}. If so, it can be used to find nth roots as follows.

To find \sqrt[10]{2} or 2^{\frac{1}{10}} press 2 x1/y 10 =

The answer should be 1.071773463.

We explore the nth root further in the worked example below.

5

Find \sqrt[10]{100} to 3 s.f. without using the x^\frac{1}{y} or \sqrt[x]{\ } function on your calculator. You may use the x^y function.

(Try simpler examples like \sqrt{100} or \sqrt[3]{100} first if you’re not sure how to do this.)

Repeat for \sqrt[100]{1\ 000\ 000\ 000} and \sqrt[10]{0.1}.

Show me

\sqrt[10]{100} = 100^{\frac{1}{10}} = 100^{0.1} = 1.5848931...

(\sqrt{100} = 100^{\frac{1}{2}} = 10   \sqrt[3]{100} = 100^{\frac{1}{3}} = 4.6415888... )

\sqrt[100]{1 000 000 000} = 1 000 000 000^{0.01} = 1.23026877...   \sqrt[10]{0.1} = 0.1^{0.1} = 0.7943282...

The bacteria problem presented earlier is an example of 'exponential' growth. In this case, the exponential growth is defined as a growth whereby the number of bacteria present is multiplied by 4 every hour.

Exponential growth occurs in many situations and fractional indices are often very useful. A good example concerns credit card accounts where any unpaid debt grows exponentially by a certain percentage each month. Credit cards quote a monthly interest rate and the equivalent APR (annual percentage rate).

A typical APR is 29.84%. This means that a debt of £100 at the start of the year becomes one of £129.84 by the end. However, the interest is worked out monthly at a monthly rate of 2.2%.

This figure arises because

(1.022)^{12} = 1.2984

giving an APR of (1.2984 − 1) × 100%.

Another way of writing this is to say

1.2984^{\frac{1}{12}} = 1.022

6

What is the monthly interest rate if the APR is 34.45% ?

Show me

Since

(1.3445)^{\frac{1}{12}} = 1.02498...,

monthly interest rate = 2.5%.

7

Joel has an outstanding credit card bill of £162. The APR is 30.23%. He leaves it two months before paying. How much does he have to pay?

Show me

2 months is of a year.

But

(1.3023)^{\frac{1}{6}} = 1.045

and

1.045 × 162 = £169.29, the amount Joe has to pay.

Exercises

Calculate these without a calculator:

(a)
16^{\frac{1}{2}}
(b)
8^{\frac{1}{3}}
(c)
81^{\frac{1}{4}}
(d)
\left(\frac{1}{4}\right)^{\frac{1}{2}}
(e)
\left(\frac{16}{625}\right)^{\frac{1}{4}}
(f)
(-1)^{\frac{1}{3}}

Use a calculator to work these out to 3 s.f.

(a)
6^{\frac{1}{2}}
(b)
10^{\frac{1}{3}}
(c)
56^{\frac{1}{5}}
(d)
(0.03)^{\frac{1}{20}}
(e)
(0.5)^{\frac{1}{2}}

Solve these equations:

(a)
4x = 2 x =
(b)
125x = 5 x =
(c)
100000x = 10 x =
(d)
81x = x =

The APR on credit cards is 26.08%.

(a)

Jan has an outstanding bill of £365. To how much does this grow in 6 months, assuming no other transactions take place?

£
(b)

Mark has a bill of £218. What is his bill a month later?

£

Water lilies on a pond grow exponentially so that the area they cover doubles every week. On Sunday they cover 13% of the surface. What percentage do they cover on Monday?

%

An investment policy boasts exponential growth and guarantees to treble your investment, at least, over 20 years. Work out the minimum guaranteed value, to the nearest pound, of

(a)

a £600 investment after 5 years;

£
(b)

a £1000 investment after 10 years;

£
(c)

a £2400 investment after 4 years.

£