When two events take place, and every outcome is equally likely to happen, the probability of a particular combined outcome can be readily found from the formula
probability =
The following examples show how this formula is used.
Worked Examples
Two dice are thrown together. Find the probability that the total score is 9.
The table shows all the possible outcomes and total scores.
| Second dice | |||||||
| 1 | 2 | 3 | 4 | 5 | 6 | ||
| First dice | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
| 2 | 3 | 4 | 5 | 6 | 7 | 8 | |
| 3 | 4 | 5 | 6 | 7 | 8 | 9 | |
| 4 | 5 | 6 | 7 | 8 | 9 | 10 | |
| 5 | 6 | 7 | 8 | 9 | 10 | 11 | |
| 6 | 7 | 8 | 9 | 10 | 11 | 12 | |
There are 36 possible outcomes, and each one is equally likely to occur.
The outcomes that give a total of 9 have been circled. There are 4 such outcomes.
Now the probability can be found.
P(9) = =
A spinner that forms part of a children's game can point to one of four regions, A, B, C or D, when spun. What is the probability that when two children spin the spinner, it points to the same letter?
The table shows all the possible outcomes.
| Second child | |||||
| A | B | C | D | ||
| First child | A | AA | AB | AC | AD |
| B | BA | BB | BC | BD | |
| C | CA | CB | CC | CD | |
| D | DA | DB | DC | DD | |
There are 16 possible outcomes. Each is equally likely to occur. The outcomes that are the same for both children have been circled. There are four outcomes of this type.
The probability that both have the same letter is
=
