Pythagoras' Theorem
Further Work with Pythagoras' Theorem
Worked Examples
1
Find the length of the side marked x in the diagram.
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First consider triangle ABC. The unknown length of the hypotenuse has been marked y.
| y2 | = (4 cm)2 + (4 cm)2 |
| y2 | = 16 cm2 + 16 cm2 |
| y2 | = 32 cm2 |
Triangle ACD can now be considered, using the value for y2. From the triangle, x2 = y2 + 22 , and using y2 = 32 cm2 gives
| x2 | = 32 cm2 + 4 cm2 |
| x2 | = 36 cm2 |
| x | = 36 cm2 |
| x | = 6 cm |
Note
When finding the side x, it is not necessary to find , but to simply use y2 = 32 cm2 .
2
Find the value of x as shown on the diagram.
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Using Pythagoras' Theorem gives
| 132 | = (2x)2 + (3x)2 | |
| 169 | = 4x2 + 9x2 | (since (2x)2 = 22 x2 = 4x2 ) |
| 169 | = 13x2 | |
| 13 | = x2 | |
| x | = | |
| = 3.61 m | (to 2 decimal places) |
Exercises
On this page give your answers rounded to 2 decimal places when necessary, unless otherwise instructed.
