If the lengths of any two sides of a right angled triangle are known, then sine, cosine and tangent can be used to find the angles of the triangle.
Worked Examples
Find the angle marked θ in the triangle shown.
In this triangle,
hypotenuse = 20 cm
opposite = 14 cm
Usingsinθ =
| gives | sinθ | = |
| = 0.7 |
So θ = sin−1(0.7)
and using the and buttons on a calculator gives θ = 44.4° (to 1 d.p.)
Find the angle marked θ in the triangle shown.
In this triangle,
opposite = 25 cm
adjacent = 4 cm
Usingtanθ =
| gives | tanθ | = |
| = 6.25 |
Soθ = tan−1(6.25)
and using the and buttons on a calculator gives θ = 80.9° (to 1 d.p.)

The diagram above shows triangle PQR, not drawn to scale.
PQ = 20 cm, ∠QPR = 30°, QS is perpendicular to PR, SR = 9 cm, and ∠SQR = x° .
Calculate
the length of QS
Show me| QS | = 20 sin30° |
| = 10 cm |
the size of angle x to the nearest degree.
Show me| tanx | = |
| = 0.9 | |
| x | = tan−1(0.9) |
and using the and buttons on a calculator gives
x ≈ 41.987° ≈ 42° to the nearest degree.
