x² + 5x + 6 = 0

by factorisation.x = or

x² – 5x – 6 = 0

by factorisation.x = or

x² – 2x = 0

x = or

9x² – 64 = 0

x =		or

x² – 6x + 9 = 0

x =

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x² – 6x – 8 = 0

has solutions of the form

x = a ±

where a and b are integers.

(a) What is the value of a?a =

(b) What is the value of b?b =

x² + x + 7 = 0

Number of real solutions =

9x² + 12x + 4 = 0

Number of real solutions =

2x² + 19x – 9 = 0

to 2 d.p.x =

x² + 20x + 2

can be wrritten in the form

(x + a)² – b

where a and b are integers.

(a) What is the value of a?a =

(b) What is the value of b?b =

Hence show that the solutions of

x² + 20x +2 = 0

are of the form x = c ± d where c and d are integers.

(c) What is the value of c?c =

(d) What is the value of d?d =

(e) What is the minimum value of x² + 20x + 2?
Minimum value =

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