Initial Diagnostic Audit - Unit I1: Pythagoras' Theorem and Trigonometric Ratios
Section I1.1 - Pythagoras' Theorem

For each of the diagrams below, calculate the value of x.

1.
x = cm  
2.
x = cm  
3.
x = cm Give your answer correct to 2 d.p.  
4.
x = cm Give your answer correct to 2 d.p.  
5. The diagram below shows the cross-section of a shed.

Calculate the length, AB, of the roof, giving your answer in metres, correct to two decimal places.
AB = m
Section I1.2 - Further Work with Pythagoras' Theorem

For each of the diagrams below, calculate the length of the side marked x.
Give your answers correct to 1 d.p.

6.
  x = cm
7.
  x = cm
8.
  x = cm
9. Which of these triangles is a right angled triangle?


10. A toy is made from a cone attached to a wedge, as shown in the cross section diagram below.


What is the height of the cone? Give your answer to the nearest mm. Height = cm

Section I1.3 - Sine, Cosine and Tangent
11. In the triangle below, which is the adjacent side for the angle θ?.
12. For the triangle below, give the value of sinθ, cosθ and tanθ as a fraction.
(a)   sinθ
  
  
(b)   cosθ
  
(c)   tanθ
  
13. Use your calculator to find the angle θ to one decimal place, if sinθ = 0.65
θ = °
Section I1.4 - Finding Lengths in Right Angled Triangles
14. What are the values of x and y in the right angled triangle below?
Give your answers to 1 d.p.

(a)  x = cm

(b)  y = cm

15. What is the length of AB in the right angled triangle below?
Give your answer to 1 d.p.

AB = cm

16. What is the value of x in the triangles below?
Give your answers to 1 d.p.

x = m

17. What is the value of x in the triangles below?
Give your answers to 1 d.p.

x = cm

Section I1.5 - Finding Angles in Right Angled Triangles

Find the angle θ , to the nearest whole number, for each of these right angled triangles.

18.
  θ = °
19.
  θ = °
20.
  θ = °
21. The diagram below shows a simple bridge, supported by four steel cables.

Calculate the angles α and β shown, giving your answers to 1 d.p.

(a)  α = °

(b)  β = °


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Produced by Russell Geach for CIMT - August 2014